Consequences of Deleting Recovery Partition (G53) ?

Hello,
A lot of questions had been asked about manipulating built-in recovery partition, but i couldn't find a good answer on those questions which are puzzling me.

As you know, the built-in "hidden" recovery partition consumes a lot of space as much as 21,49 GB on HDD and it's recommended to delete it. But, on the other hand, the system is configured to use that built-in recovery partition in case of system failure by hitting F9 and selecting Windows Setup [EMS Enabled] during boot through recovery console similar to the screen below:



And, worse,i beleive the hidden recovery partition holds some info in bootloader so i suspect deleting it would cause system boot failure.

I want to delete the recovery partition but keeping current default Windows 7 installation at the same time. So, if i just direclty delete the recovery partition like in the screenshot below, what would happen?

1) Will my system crash at boot, and will i have to do a complete_drive_format and reinstall OS after deleting recovery partition?
2) What will happen from now on, if i hit F9 after deleting recovery partition?
3) Will i have to merge the blank space of deleted recovery partition (21,49 GB) with C: ?

I'm lost and suspicious about the consequences, remembering Murphy laws.

I'm also attaching my current (and factory-default) partitioning structure of my single Seagate drive here.
Thanks in advance.

 

The only drawback is the lack of an easy recovery of the OS if it gets corrupted.

 

Mauby beter save it on external hard drive with Acronis ?

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You can, though sometimes it does not want to go back properly.

 

So, the system can boot fine but i lose the option of easy recovery via F9? Is this the only risk that i can take?

 

Yes, so I would advise taking and storing your own backup image somewhere else as a replacement option.